** Next:** About this document ...
**Up:** Quiz8
** Previous:** Exercise 2.

Translate the following C-like piece of code into three-address code.
a = x * y + u * v - w * t;
b = w * t - m * n;
while (b != 0) {
tmp = a;
a = b;
while (tmp > b) {
tmp = tmp - b;
}
b = tmp;
}

The three-address code instructions you may need are of one of the forms:
`goto L` where is a symbolic label (like `L1, L2, ...`)
`if x relop y goto L` where `relop` can be `=` or `< `
`x:= y op z` where `op` can be `-`, `-` and `*`

Moreover your solution does **not** need to be obtained by one of the
algorithms of the course.
Just consider that you are programming a very basic calculator.

**Answer 3**
*
*

** Next:** About this document ...
**Up:** Quiz8
** Previous:** Exercise 2.
*Marc Moreno Maza *

2004-12-02